4x^2-38X+60=0

Solution for 4x^2-38X+60=0 equation:

4x^2-38x+60=0

a = 4; b = -38; c = +60;
Δ = b2-4ac
Δ = -382-4·4·60
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-22}{2*4}=\frac{16}{8}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+22}{2*4}=\frac{60}{8}
=7+1/2
$